Metamath Proof Explorer


Theorem nne

Description: Negation of inequality. (Contributed by NM, 9-Jun-2006)

Ref Expression
Assertion nne
|- ( -. A =/= B <-> A = B )

Proof

Step Hyp Ref Expression
1 df-ne
 |-  ( A =/= B <-> -. A = B )
2 1 con2bii
 |-  ( A = B <-> -. A =/= B )
3 2 bicomi
 |-  ( -. A =/= B <-> A = B )