Metamath Proof Explorer


Theorem offun

Description: The function operation produces a function. (Contributed by SN, 23-Jul-2024)

Ref Expression
Hypotheses offun.1
|- ( ph -> F Fn A )
offun.2
|- ( ph -> G Fn B )
offun.3
|- ( ph -> A e. V )
offun.4
|- ( ph -> B e. W )
Assertion offun
|- ( ph -> Fun ( F oF R G ) )

Proof

Step Hyp Ref Expression
1 offun.1
 |-  ( ph -> F Fn A )
2 offun.2
 |-  ( ph -> G Fn B )
3 offun.3
 |-  ( ph -> A e. V )
4 offun.4
 |-  ( ph -> B e. W )
5 eqid
 |-  ( A i^i B ) = ( A i^i B )
6 1 2 3 4 5 offn
 |-  ( ph -> ( F oF R G ) Fn ( A i^i B ) )
7 fnfun
 |-  ( ( F oF R G ) Fn ( A i^i B ) -> Fun ( F oF R G ) )
8 6 7 syl
 |-  ( ph -> Fun ( F oF R G ) )