Metamath Proof Explorer


Theorem opprbas

Description: Base set of an opposite ring. (Contributed by Mario Carneiro, 1-Dec-2014)

Ref Expression
Hypotheses opprbas.1
|- O = ( oppR ` R )
opprbas.2
|- B = ( Base ` R )
Assertion opprbas
|- B = ( Base ` O )

Proof

Step Hyp Ref Expression
1 opprbas.1
 |-  O = ( oppR ` R )
2 opprbas.2
 |-  B = ( Base ` R )
3 df-base
 |-  Base = Slot 1
4 1nn
 |-  1 e. NN
5 1lt3
 |-  1 < 3
6 1 3 4 5 opprlem
 |-  ( Base ` R ) = ( Base ` O )
7 2 6 eqtri
 |-  B = ( Base ` O )