Metamath Proof Explorer


Theorem opprbas

Description: Base set of an opposite ring. (Contributed by Mario Carneiro, 1-Dec-2014) (Proof shortened by AV, 6-Nov-2024)

Ref Expression
Hypotheses opprbas.1
|- O = ( oppR ` R )
opprbas.2
|- B = ( Base ` R )
Assertion opprbas
|- B = ( Base ` O )

Proof

Step Hyp Ref Expression
1 opprbas.1
 |-  O = ( oppR ` R )
2 opprbas.2
 |-  B = ( Base ` R )
3 baseid
 |-  Base = Slot ( Base ` ndx )
4 basendxnmulrndx
 |-  ( Base ` ndx ) =/= ( .r ` ndx )
5 1 3 4 opprlem
 |-  ( Base ` R ) = ( Base ` O )
6 2 5 eqtri
 |-  B = ( Base ` O )