Theorem rbaibd

Description: Move conjunction outside of biconditional. (Contributed by Mario Carneiro, 11-Sep-2015)

	Ref	Expression
Hypothesis	baibd.1	|- ( ph -> ( ps <-> ( ch /\ th ) ) )
Assertion	rbaibd	|- ( ( ph /\ th ) -> ( ps <-> ch ) )

Proof

Step	Hyp	Ref	Expression
1		baibd.1	|- ( ph -> ( ps <-> ( ch /\ th ) ) )
2	1	biancomd	|- ( ph -> ( ps <-> ( th /\ ch ) ) )
3	2	baibd	|- ( ( ph /\ th ) -> ( ps <-> ch ) )