Metamath Proof Explorer


Theorem rnghmf

Description: A ring homomorphism is a function. (Contributed by AV, 23-Feb-2020)

Ref Expression
Hypotheses rnghmf.b
|- B = ( Base ` R )
rnghmf.c
|- C = ( Base ` S )
Assertion rnghmf
|- ( F e. ( R RngHomo S ) -> F : B --> C )

Proof

Step Hyp Ref Expression
1 rnghmf.b
 |-  B = ( Base ` R )
2 rnghmf.c
 |-  C = ( Base ` S )
3 rnghmghm
 |-  ( F e. ( R RngHomo S ) -> F e. ( R GrpHom S ) )
4 1 2 ghmf
 |-  ( F e. ( R GrpHom S ) -> F : B --> C )
5 3 4 syl
 |-  ( F e. ( R RngHomo S ) -> F : B --> C )