Metamath Proof Explorer


Theorem rnghmf

Description: A ring homomorphism is a function. (Contributed by AV, 23-Feb-2020)

Ref Expression
Hypotheses rnghmf.b 𝐵 = ( Base ‘ 𝑅 )
rnghmf.c 𝐶 = ( Base ‘ 𝑆 )
Assertion rnghmf ( 𝐹 ∈ ( 𝑅 RngHomo 𝑆 ) → 𝐹 : 𝐵𝐶 )

Proof

Step Hyp Ref Expression
1 rnghmf.b 𝐵 = ( Base ‘ 𝑅 )
2 rnghmf.c 𝐶 = ( Base ‘ 𝑆 )
3 rnghmghm ( 𝐹 ∈ ( 𝑅 RngHomo 𝑆 ) → 𝐹 ∈ ( 𝑅 GrpHom 𝑆 ) )
4 1 2 ghmf ( 𝐹 ∈ ( 𝑅 GrpHom 𝑆 ) → 𝐹 : 𝐵𝐶 )
5 3 4 syl ( 𝐹 ∈ ( 𝑅 RngHomo 𝑆 ) → 𝐹 : 𝐵𝐶 )