Metamath Proof Explorer


Theorem ghmf

Description: A group homomorphism is a function. (Contributed by Stefan O'Rear, 31-Dec-2014)

Ref Expression
Hypotheses ghmf.x ⊢ 𝑋 = ( Base ‘ 𝑆 )
ghmf.y ⊢ 𝑌 = ( Base ‘ 𝑇 )
Assertion ghmf ( 𝐹 ∈ ( 𝑆 GrpHom 𝑇 ) → 𝐹 : 𝑋 ⟶ 𝑌 )

Proof

Step Hyp Ref Expression
1 ghmf.x ⊢ 𝑋 = ( Base ‘ 𝑆 )
2 ghmf.y ⊢ 𝑌 = ( Base ‘ 𝑇 )
3 eqid ⊢ ( +g ‘ 𝑆 ) = ( +g ‘ 𝑆 )
4 eqid ⊢ ( +g ‘ 𝑇 ) = ( +g ‘ 𝑇 )
5 1 2 3 4 isghm ⊢ ( 𝐹 ∈ ( 𝑆 GrpHom 𝑇 ) ↔ ( ( 𝑆 ∈ Grp ∧ 𝑇 ∈ Grp ) ∧ ( 𝐹 : 𝑋 ⟶ 𝑌 ∧ ∀ 𝑦 ∈ 𝑋 ∀ 𝑥 ∈ 𝑋 ( 𝐹 ‘ ( 𝑦 ( +g ‘ 𝑆 ) 𝑥 ) ) = ( ( 𝐹 ‘ 𝑦 ) ( +g ‘ 𝑇 ) ( 𝐹 ‘ 𝑥 ) ) ) ) )
6 5 simprbi ⊢ ( 𝐹 ∈ ( 𝑆 GrpHom 𝑇 ) → ( 𝐹 : 𝑋 ⟶ 𝑌 ∧ ∀ 𝑦 ∈ 𝑋 ∀ 𝑥 ∈ 𝑋 ( 𝐹 ‘ ( 𝑦 ( +g ‘ 𝑆 ) 𝑥 ) ) = ( ( 𝐹 ‘ 𝑦 ) ( +g ‘ 𝑇 ) ( 𝐹 ‘ 𝑥 ) ) ) )
7 6 simpld ⊢ ( 𝐹 ∈ ( 𝑆 GrpHom 𝑇 ) → 𝐹 : 𝑋 ⟶ 𝑌 )