Metamath Proof Explorer


Theorem sinhf

Description: Domain and codomain of the sinh function. (Contributed by Jon Pennant, 9-Sep-2026)

Ref Expression
Assertion sinhf
|- sinh : CC --> CC

Proof

Step Hyp Ref Expression
1 df-sinh
 |-  sinh = ( x e. CC |-> ( ( sin ` ( _i x. x ) ) / _i ) )
2 ax-icn
 |-  _i e. CC
3 2 a1i
 |-  ( x e. CC -> _i e. CC )
4 id
 |-  ( x e. CC -> x e. CC )
5 3 4 mulcld
 |-  ( x e. CC -> ( _i x. x ) e. CC )
6 5 sincld
 |-  ( x e. CC -> ( sin ` ( _i x. x ) ) e. CC )
7 ine0
 |-  _i =/= 0
8 7 a1i
 |-  ( x e. CC -> _i =/= 0 )
9 6 3 8 divcld
 |-  ( x e. CC -> ( ( sin ` ( _i x. x ) ) / _i ) e. CC )
10 1 9 fmpti
 |-  sinh : CC --> CC