Metamath Proof Explorer


Theorem ssex

Description: A subclass of a set is a set. Exercise 3 of TakeutiZaring p. 22. This is one way to express the Axiom of Separation ax-sep (a.k.a. Subset Axiom). (Contributed by NM, 27-Apr-1994) (Proof shortened by BJ, 18-Jul-2026)

Ref Expression
Hypothesis ssex.1
|- B e. _V
Assertion ssex
|- ( A C_ B -> A e. _V )

Proof

Step Hyp Ref Expression
1 ssex.1
 |-  B e. _V
2 ssexg
 |-  ( ( A C_ B /\ B e. _V ) -> A e. _V )
3 1 2 mpan2
 |-  ( A C_ B -> A e. _V )