Metamath Proof Explorer


Theorem ssex

Description: A subclass of a set is a set. Exercise 3 of TakeutiZaring p. 22. This is one way to express the Axiom of Separation ax-sep (a.k.a. Subset Axiom). (Contributed by NM, 27-Apr-1994) (Proof shortened by BJ, 18-Jul-2026)

Ref Expression
Hypothesis ssex.1 ⊢ 𝐵 ∈ V
Assertion ssex ( 𝐴 ⊆ 𝐵 → 𝐴 ∈ V )

Proof

Step Hyp Ref Expression
1 ssex.1 ⊢ 𝐵 ∈ V
2 ssexg ⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ∈ V ) → 𝐴 ∈ V )
3 1 2 mpan2 ⊢ ( 𝐴 ⊆ 𝐵 → 𝐴 ∈ V )