Metamath Proof Explorer


Theorem subrgccidom

Description: A subring of the complex numbers is an integral domain. (Contributed by AV, 26-Oct-2026)

Ref Expression
Hypotheses subrgcccrng.r
|- R = ( CCfld |`s S )
subrgcccrng.s
|- S e. ( SubRing ` CCfld )
Assertion subrgccidom
|- R e. IDomn

Proof

Step Hyp Ref Expression
1 subrgcccrng.r
 |-  R = ( CCfld |`s S )
2 subrgcccrng.s
 |-  S e. ( SubRing ` CCfld )
3 1 2 subrgcccrng
 |-  R e. CRing
4 1 2 subrgccdom
 |-  R e. Domn
5 isidom
 |-  ( R e. IDomn <-> ( R e. CRing /\ R e. Domn ) )
6 3 4 5 mpbir2an
 |-  R e. IDomn