Metamath Proof Explorer
Description: A subring of the complex numbers is an integral domain. (Contributed by AV, 26-Oct-2026)
|
|
Ref |
Expression |
|
Hypotheses |
subrgcccrng.r |
⊢ 𝑅 = ( ℂfld ↾s 𝑆 ) |
|
|
subrgcccrng.s |
⊢ 𝑆 ∈ ( SubRing ‘ ℂfld ) |
|
Assertion |
subrgccidom |
⊢ 𝑅 ∈ IDomn |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
subrgcccrng.r |
⊢ 𝑅 = ( ℂfld ↾s 𝑆 ) |
| 2 |
|
subrgcccrng.s |
⊢ 𝑆 ∈ ( SubRing ‘ ℂfld ) |
| 3 |
1 2
|
subrgcccrng |
⊢ 𝑅 ∈ CRing |
| 4 |
1 2
|
subrgccdom |
⊢ 𝑅 ∈ Domn |
| 5 |
|
isidom |
⊢ ( 𝑅 ∈ IDomn ↔ ( 𝑅 ∈ CRing ∧ 𝑅 ∈ Domn ) ) |
| 6 |
3 4 5
|
mpbir2an |
⊢ 𝑅 ∈ IDomn |