Metamath Proof Explorer


Theorem subrgccdom

Description: A subring of the complex numbers is a domain. (Contributed by AV, 26-Oct-2026)

Ref Expression
Hypotheses subrgcccrng.r ⊢ 𝑅 = ( ℂfld ↾s 𝑆 )
subrgcccrng.s ⊢ 𝑆 ∈ ( SubRing ‘ ℂfld )
Assertion subrgccdom 𝑅 ∈ Domn

Proof

Step Hyp Ref Expression
1 subrgcccrng.r ⊢ 𝑅 = ( ℂfld ↾s 𝑆 )
2 subrgcccrng.s ⊢ 𝑆 ∈ ( SubRing ‘ ℂfld )
3 1 2 subrgccnzr ⊢ 𝑅 ∈ NzRing
4 subrgccsscc ⊢ ( 𝑆 ∈ ( SubRing ‘ ℂfld ) → 𝑆 ⊆ ℂ )
5 2 4 ax-mp ⊢ 𝑆 ⊆ ℂ
6 5 sseli ⊢ ( 𝑥 ∈ 𝑆 → 𝑥 ∈ ℂ )
7 5 sseli ⊢ ( 𝑦 ∈ 𝑆 → 𝑦 ∈ ℂ )
8 mul0or ⊢ ( ( 𝑥 ∈ ℂ ∧ 𝑦 ∈ ℂ ) → ( ( 𝑥 · 𝑦 ) = 0 ↔ ( 𝑥 = 0 ∨ 𝑦 = 0 ) ) )
9 6 7 8 syl2an ⊢ ( ( 𝑥 ∈ 𝑆 ∧ 𝑦 ∈ 𝑆 ) → ( ( 𝑥 · 𝑦 ) = 0 ↔ ( 𝑥 = 0 ∨ 𝑦 = 0 ) ) )
10 9 biimpd ⊢ ( ( 𝑥 ∈ 𝑆 ∧ 𝑦 ∈ 𝑆 ) → ( ( 𝑥 · 𝑦 ) = 0 → ( 𝑥 = 0 ∨ 𝑦 = 0 ) ) )
11 10 rgen2 ⊢ ∀ 𝑥 ∈ 𝑆 ∀ 𝑦 ∈ 𝑆 ( ( 𝑥 · 𝑦 ) = 0 → ( 𝑥 = 0 ∨ 𝑦 = 0 ) )
12 1 cnfldsrngbas ⊢ ( 𝑆 ⊆ ℂ → 𝑆 = ( Base ‘ 𝑅 ) )
13 5 12 ax-mp ⊢ 𝑆 = ( Base ‘ 𝑅 )
14 eqid ⊢ ( ℂfld ↾s 𝑆 ) = ( ℂfld ↾s 𝑆 )
15 14 cnfldsrngmul ⊢ ( 𝑆 ∈ ( SubRing ‘ ℂfld ) → · = ( .r ‘ ( ℂfld ↾s 𝑆 ) ) )
16 2 15 ax-mp ⊢ · = ( .r ‘ ( ℂfld ↾s 𝑆 ) )
17 1 fveq2i ⊢ ( .r ‘ 𝑅 ) = ( .r ‘ ( ℂfld ↾s 𝑆 ) )
18 16 17 eqtr4i ⊢ · = ( .r ‘ 𝑅 )
19 1 2 subrgcccrng0 ⊢ 0 = ( 0g ‘ 𝑅 )
20 13 18 19 isdomn ⊢ ( 𝑅 ∈ Domn ↔ ( 𝑅 ∈ NzRing ∧ ∀ 𝑥 ∈ 𝑆 ∀ 𝑦 ∈ 𝑆 ( ( 𝑥 · 𝑦 ) = 0 → ( 𝑥 = 0 ∨ 𝑦 = 0 ) ) ) )
21 3 11 20 mpbir2an ⊢ 𝑅 ∈ Domn