Metamath Proof Explorer


Theorem subrgccdom

Description: A subring of the complex numbers is a domain. (Contributed by AV, 26-Oct-2026)

Ref Expression
Hypotheses subrgcccrng.r ⊢ R = ℂ fld ↾ 𝑠 S
subrgcccrng.s ⊢ S ∈ SubRing ⁡ ℂ fld
Assertion subrgccdom ⊢ R ∈ Domn

Proof

Step Hyp Ref Expression
1 subrgcccrng.r ⊢ R = ℂ fld ↾ 𝑠 S
2 subrgcccrng.s ⊢ S ∈ SubRing ⁡ ℂ fld
3 1 2 subrgccnzr ⊢ R ∈ NzRing
4 subrgccsscc ⊢ S ∈ SubRing ⁡ ℂ fld → S ⊆ ℂ
5 2 4 ax-mp ⊢ S ⊆ ℂ
6 5 sseli ⊢ x ∈ S → x ∈ ℂ
7 5 sseli ⊢ y ∈ S → y ∈ ℂ
8 mul0or ⊢ x ∈ ℂ ∧ y ∈ ℂ → x ⁢ y = 0 ↔ x = 0 ∨ y = 0
9 6 7 8 syl2an ⊢ x ∈ S ∧ y ∈ S → x ⁢ y = 0 ↔ x = 0 ∨ y = 0
10 9 biimpd ⊢ x ∈ S ∧ y ∈ S → x ⁢ y = 0 → x = 0 ∨ y = 0
11 10 rgen2 ⊢ ∀ x ∈ S ∀ y ∈ S x ⁢ y = 0 → x = 0 ∨ y = 0
12 1 cnfldsrngbas ⊢ S ⊆ ℂ → S = Base R
13 5 12 ax-mp ⊢ S = Base R
14 eqid ⊢ ℂ fld ↾ 𝑠 S = ℂ fld ↾ 𝑠 S
15 14 cnfldsrngmul ⊢ S ∈ SubRing ⁡ ℂ fld → × = ⋅ ℂ fld ↾ 𝑠 S
16 2 15 ax-mp ⊢ × = ⋅ ℂ fld ↾ 𝑠 S
17 1 fveq2i ⊢ ⋅ R = ⋅ ℂ fld ↾ 𝑠 S
18 16 17 eqtr4i ⊢ × = ⋅ R
19 1 2 subrgcccrng0 ⊢ 0 = 0 R
20 13 18 19 isdomn ⊢ R ∈ Domn ↔ R ∈ NzRing ∧ ∀ x ∈ S ∀ y ∈ S x ⁢ y = 0 → x = 0 ∨ y = 0
21 3 11 20 mpbir2an ⊢ R ∈ Domn