Metamath Proof Explorer


Theorem syl5rbb

Description: A syllogism inference from two biconditionals. (Contributed by NM, 1-Aug-1993)

Ref Expression
Hypotheses syl5rbb.1
|- ( ph <-> ps )
syl5rbb.2
|- ( ch -> ( ps <-> th ) )
Assertion syl5rbb
|- ( ch -> ( th <-> ph ) )

Proof

Step Hyp Ref Expression
1 syl5rbb.1
 |-  ( ph <-> ps )
2 syl5rbb.2
 |-  ( ch -> ( ps <-> th ) )
3 1 2 syl5bb
 |-  ( ch -> ( ph <-> th ) )
4 3 bicomd
 |-  ( ch -> ( th <-> ph ) )