Metamath Proof Explorer


Theorem syl5bb

Description: A syllogism inference from two biconditionals. (Contributed by NM, 12-Mar-1993)

Ref Expression
Hypotheses syl5bb.1
|- ( ph <-> ps )
syl5bb.2
|- ( ch -> ( ps <-> th ) )
Assertion syl5bb
|- ( ch -> ( ph <-> th ) )

Proof

Step Hyp Ref Expression
1 syl5bb.1
 |-  ( ph <-> ps )
2 syl5bb.2
 |-  ( ch -> ( ps <-> th ) )
3 1 a1i
 |-  ( ch -> ( ph <-> ps ) )
4 3 2 bitrd
 |-  ( ch -> ( ph <-> th ) )