Metamath Proof Explorer


Theorem syl6eqr

Description: An equality transitivity deduction. (Contributed by NM, 21-Jun-1993)

Ref Expression
Hypotheses syl6eqr.1
|- ( ph -> A = B )
syl6eqr.2
|- C = B
Assertion syl6eqr
|- ( ph -> A = C )

Proof

Step Hyp Ref Expression
1 syl6eqr.1
 |-  ( ph -> A = B )
2 syl6eqr.2
 |-  C = B
3 2 eqcomi
 |-  B = C
4 1 3 syl6eq
 |-  ( ph -> A = C )