Metamath Proof Explorer


Theorem syl6rbb

Description: A syllogism inference from two biconditionals. (Contributed by NM, 5-Aug-1993)

Ref Expression
Hypotheses syl6rbb.1
|- ( ph -> ( ps <-> ch ) )
syl6rbb.2
|- ( ch <-> th )
Assertion syl6rbb
|- ( ph -> ( th <-> ps ) )

Proof

Step Hyp Ref Expression
1 syl6rbb.1
 |-  ( ph -> ( ps <-> ch ) )
2 syl6rbb.2
 |-  ( ch <-> th )
3 1 2 syl6bb
 |-  ( ph -> ( ps <-> th ) )
4 3 bicomd
 |-  ( ph -> ( th <-> ps ) )