Metamath Proof Explorer


Theorem syl6bbr

Description: A syllogism inference from two biconditionals. (Contributed by NM, 12-Mar-1993)

Ref Expression
Hypotheses syl6bbr.1
|- ( ph -> ( ps <-> ch ) )
syl6bbr.2
|- ( th <-> ch )
Assertion syl6bbr
|- ( ph -> ( ps <-> th ) )

Proof

Step Hyp Ref Expression
1 syl6bbr.1
 |-  ( ph -> ( ps <-> ch ) )
2 syl6bbr.2
 |-  ( th <-> ch )
3 2 bicomi
 |-  ( ch <-> th )
4 1 3 syl6bb
 |-  ( ph -> ( ps <-> th ) )