Metamath Proof Explorer


Theorem syl6rbbr

Description: A syllogism inference from two biconditionals. (Contributed by NM, 25-Nov-1994)

Ref Expression
Hypotheses syl6rbbr.1
|- ( ph -> ( ps <-> ch ) )
syl6rbbr.2
|- ( th <-> ch )
Assertion syl6rbbr
|- ( ph -> ( th <-> ps ) )

Proof

Step Hyp Ref Expression
1 syl6rbbr.1
 |-  ( ph -> ( ps <-> ch ) )
2 syl6rbbr.2
 |-  ( th <-> ch )
3 2 bicomi
 |-  ( ch <-> th )
4 1 3 syl6rbb
 |-  ( ph -> ( th <-> ps ) )