Metamath Proof Explorer


Theorem tgaas

Description: Angle-angle-side: two triangles with two congruent angles and a congruent side not included between them are congruent. The side included between the two angles is congruent by tgaas1 , which reduces the theorem to SAS ( tgsas ). (Contributed by JAG, 12-Aug-2026)

Ref Expression
Hypotheses tgaas1.p
|- P = ( Base ` G )
tgaas1.m
|- .- = ( dist ` G )
tgaas1.i
|- I = ( Itv ` G )
tgaas1.l
|- L = ( LineG ` G )
tgaas1.g
|- ( ph -> G e. TarskiG )
tgaas1.a
|- ( ph -> A e. P )
tgaas1.b
|- ( ph -> B e. P )
tgaas1.c
|- ( ph -> C e. P )
tgaas1.d
|- ( ph -> D e. P )
tgaas1.e
|- ( ph -> E e. P )
tgaas1.f
|- ( ph -> F e. P )
tgaas1.ncol
|- ( ph -> -. ( C e. ( A L B ) \/ A = B ) )
tgaas1.1
|- ( ph -> ( A .- B ) = ( D .- E ) )
tgaas1.2
|- ( ph -> <" A B C "> ( cgrA ` G ) <" D E F "> )
tgaas1.3
|- ( ph -> <" B C A "> ( cgrA ` G ) <" E F D "> )
Assertion tgaas
|- ( ph -> <" A B C "> ( cgrG ` G ) <" D E F "> )

Proof

Step Hyp Ref Expression
1 tgaas1.p
 |-  P = ( Base ` G )
2 tgaas1.m
 |-  .- = ( dist ` G )
3 tgaas1.i
 |-  I = ( Itv ` G )
4 tgaas1.l
 |-  L = ( LineG ` G )
5 tgaas1.g
 |-  ( ph -> G e. TarskiG )
6 tgaas1.a
 |-  ( ph -> A e. P )
7 tgaas1.b
 |-  ( ph -> B e. P )
8 tgaas1.c
 |-  ( ph -> C e. P )
9 tgaas1.d
 |-  ( ph -> D e. P )
10 tgaas1.e
 |-  ( ph -> E e. P )
11 tgaas1.f
 |-  ( ph -> F e. P )
12 tgaas1.ncol
 |-  ( ph -> -. ( C e. ( A L B ) \/ A = B ) )
13 tgaas1.1
 |-  ( ph -> ( A .- B ) = ( D .- E ) )
14 tgaas1.2
 |-  ( ph -> <" A B C "> ( cgrA ` G ) <" D E F "> )
15 tgaas1.3
 |-  ( ph -> <" B C A "> ( cgrA ` G ) <" E F D "> )
16 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 tgaas1
 |-  ( ph -> ( B .- C ) = ( E .- F ) )
17 1 2 3 5 6 7 8 9 10 11 13 14 16 tgsas
 |-  ( ph -> <" A B C "> ( cgrG ` G ) <" D E F "> )