Metamath Proof Explorer


Theorem tgaas

Description: Angle-angle-side: two triangles with two congruent angles and a congruent side not included between them are congruent. The side included between the two angles is congruent by tgaas1 , which reduces the theorem to SAS ( tgsas ). (Contributed by JAG, 12-Aug-2026)

Ref Expression
Hypotheses tgaas1.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
tgaas1.m ⊢ − = ( dist ‘ 𝐺 )
tgaas1.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
tgaas1.l ⊢ 𝐿 = ( LineG ‘ 𝐺 )
tgaas1.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
tgaas1.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
tgaas1.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
tgaas1.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
tgaas1.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑃 )
tgaas1.e ⊢ ( 𝜑 → 𝐸 ∈ 𝑃 )
tgaas1.f ⊢ ( 𝜑 → 𝐹 ∈ 𝑃 )
tgaas1.ncol ⊢ ( 𝜑 → ¬ ( 𝐶 ∈ ( 𝐴 𝐿 𝐵 ) ∨ 𝐴 = 𝐵 ) )
tgaas1.1 ⊢ ( 𝜑 → ( 𝐴 − 𝐵 ) = ( 𝐷 − 𝐸 ) )
tgaas1.2 ⊢ ( 𝜑 → ⟨“ 𝐴 𝐵 𝐶 ”⟩ ( cgrA ‘ 𝐺 ) ⟨“ 𝐷 𝐸 𝐹 ”⟩ )
tgaas1.3 ⊢ ( 𝜑 → ⟨“ 𝐵 𝐶 𝐴 ”⟩ ( cgrA ‘ 𝐺 ) ⟨“ 𝐸 𝐹 𝐷 ”⟩ )
Assertion tgaas ( 𝜑 → ⟨“ 𝐴 𝐵 𝐶 ”⟩ ( cgrG ‘ 𝐺 ) ⟨“ 𝐷 𝐸 𝐹 ”⟩ )

Proof

Step Hyp Ref Expression
1 tgaas1.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
2 tgaas1.m ⊢ − = ( dist ‘ 𝐺 )
3 tgaas1.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
4 tgaas1.l ⊢ 𝐿 = ( LineG ‘ 𝐺 )
5 tgaas1.g ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
6 tgaas1.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
7 tgaas1.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
8 tgaas1.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
9 tgaas1.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑃 )
10 tgaas1.e ⊢ ( 𝜑 → 𝐸 ∈ 𝑃 )
11 tgaas1.f ⊢ ( 𝜑 → 𝐹 ∈ 𝑃 )
12 tgaas1.ncol ⊢ ( 𝜑 → ¬ ( 𝐶 ∈ ( 𝐴 𝐿 𝐵 ) ∨ 𝐴 = 𝐵 ) )
13 tgaas1.1 ⊢ ( 𝜑 → ( 𝐴 − 𝐵 ) = ( 𝐷 − 𝐸 ) )
14 tgaas1.2 ⊢ ( 𝜑 → ⟨“ 𝐴 𝐵 𝐶 ”⟩ ( cgrA ‘ 𝐺 ) ⟨“ 𝐷 𝐸 𝐹 ”⟩ )
15 tgaas1.3 ⊢ ( 𝜑 → ⟨“ 𝐵 𝐶 𝐴 ”⟩ ( cgrA ‘ 𝐺 ) ⟨“ 𝐸 𝐹 𝐷 ”⟩ )
16 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 tgaas1 ⊢ ( 𝜑 → ( 𝐵 − 𝐶 ) = ( 𝐸 − 𝐹 ) )
17 1 2 3 5 6 7 8 9 10 11 13 14 16 tgsas ⊢ ( 𝜑 → ⟨“ 𝐴 𝐵 𝐶 ”⟩ ( cgrG ‘ 𝐺 ) ⟨“ 𝐷 𝐸 𝐹 ”⟩ )