Metamath Proof Explorer


Theorem weeq1

Description: Equality theorem for the well-ordering predicate. (Contributed by NM, 9-Mar-1997)

Ref Expression
Assertion weeq1
|- ( R = S -> ( R We A <-> S We A ) )

Proof

Step Hyp Ref Expression
1 freq1
 |-  ( R = S -> ( R Fr A <-> S Fr A ) )
2 soeq1
 |-  ( R = S -> ( R Or A <-> S Or A ) )
3 1 2 anbi12d
 |-  ( R = S -> ( ( R Fr A /\ R Or A ) <-> ( S Fr A /\ S Or A ) ) )
4 df-we
 |-  ( R We A <-> ( R Fr A /\ R Or A ) )
5 df-we
 |-  ( S We A <-> ( S Fr A /\ S Or A ) )
6 3 4 5 3bitr4g
 |-  ( R = S -> ( R We A <-> S We A ) )