Metamath Proof Explorer


Theorem 1psubclN

Description: The set of all atoms is a closed projective subspace. (Contributed by NM, 25-Jan-2012) (New usage is discouraged.)

Ref Expression
Hypotheses 1psubcl.a A = Atoms K
1psubcl.c C = PSubCl K
Assertion 1psubclN K HL A C

Proof

Step Hyp Ref Expression
1 1psubcl.a A = Atoms K
2 1psubcl.c C = PSubCl K
3 ssidd K HL A A
4 eqid 𝑃 K = 𝑃 K
5 1 4 pol1N K HL 𝑃 K A =
6 5 fveq2d K HL 𝑃 K 𝑃 K A = 𝑃 K
7 1 4 pol0N K HL 𝑃 K = A
8 6 7 eqtrd K HL 𝑃 K 𝑃 K A = A
9 1 4 2 ispsubclN K HL A C A A 𝑃 K 𝑃 K A = A
10 3 8 9 mpbir2and K HL A C