Metamath Proof Explorer


Theorem eqtrd

Description: An equality transitivity deduction. (Contributed by NM, 21-Jun-1993)

Ref Expression
Hypotheses eqtrd.1 φ A = B
eqtrd.2 φ B = C
Assertion eqtrd φ A = C

Proof

Step Hyp Ref Expression
1 eqtrd.1 φ A = B
2 eqtrd.2 φ B = C
3 2 eqeq2d φ A = B A = C
4 1 3 mpbid φ A = C