Metamath Proof Explorer


Theorem 1st2ndb

Description: Reconstruction of an ordered pair in terms of its components. (Contributed by NM, 25-Feb-2014)

Ref Expression
Assertion 1st2ndb ⊢ A ∈ V × V ↔ A = 1 st ⁡ A 2 nd ⁡ A

Proof

Step Hyp Ref Expression
1 1st2nd2 ⊢ A ∈ V × V → A = 1 st ⁡ A 2 nd ⁡ A
2 id ⊢ A = 1 st ⁡ A 2 nd ⁡ A → A = 1 st ⁡ A 2 nd ⁡ A
3 fvex ⊢ 1 st ⁡ A ∈ V
4 fvex ⊢ 2 nd ⁡ A ∈ V
5 3 4 opelvv ⊢ 1 st ⁡ A 2 nd ⁡ A ∈ V × V
6 2 5 eqeltrdi ⊢ A = 1 st ⁡ A 2 nd ⁡ A → A ∈ V × V
7 1 6 impbii ⊢ A ∈ V × V ↔ A = 1 st ⁡ A 2 nd ⁡ A