Metamath Proof Explorer


Theorem 2nexaln

Description: Theorem *11.25 in WhiteheadRussell p. 160. (Contributed by Andrew Salmon, 24-May-2011)

Ref Expression
Assertion 2nexaln ⊢ ¬ ∃ x ∃ y φ ↔ ∀ x ∀ y ¬ φ

Proof

Step Hyp Ref Expression
1 2exnaln ⊢ ∃ x ∃ y φ ↔ ¬ ∀ x ∀ y ¬ φ
2 1 bicomi ⊢ ¬ ∀ x ∀ y ¬ φ ↔ ∃ x ∃ y φ
3 2 con1bii ⊢ ¬ ∃ x ∃ y φ ↔ ∀ x ∀ y ¬ φ