Metamath Proof Explorer


Theorem 3eqtrrd

Description: A deduction from three chained equalities. (Contributed by NM, 4-Aug-2006) (Proof shortened by Andrew Salmon, 25-May-2011)

Ref Expression
Hypotheses 3eqtrd.1 φ A = B
3eqtrd.2 φ B = C
3eqtrd.3 φ C = D
Assertion 3eqtrrd φ D = A

Proof

Step Hyp Ref Expression
1 3eqtrd.1 φ A = B
2 3eqtrd.2 φ B = C
3 3eqtrd.3 φ C = D
4 1 2 eqtrd φ A = C
5 4 3 eqtr2d φ D = A