Metamath Proof Explorer


Theorem 3jao

Description: Disjunction of three antecedents. (Contributed by NM, 8-Apr-1994)

Ref Expression
Assertion 3jao ⊢ φ → ψ ∧ χ → ψ ∧ θ → ψ → φ ∨ χ ∨ θ → ψ

Proof

Step Hyp Ref Expression
1 jao ⊢ φ → ψ → χ → ψ → φ ∨ χ → ψ
2 df-3or ⊢ φ ∨ χ ∨ θ ↔ φ ∨ χ ∨ θ
3 jao ⊢ φ ∨ χ → ψ → θ → ψ → φ ∨ χ ∨ θ → ψ
4 2 3 syl7bi ⊢ φ ∨ χ → ψ → θ → ψ → φ ∨ χ ∨ θ → ψ
5 1 4 syl6 ⊢ φ → ψ → χ → ψ → θ → ψ → φ ∨ χ ∨ θ → ψ
6 5 3imp ⊢ φ → ψ ∧ χ → ψ ∧ θ → ψ → φ ∨ χ ∨ θ → ψ