Metamath Proof Explorer


Theorem 3orbi123i

Description: Join 3 biconditionals with disjunction. (Contributed by NM, 17-May-1994)

Ref Expression
Hypotheses bi3.1 ⊢ φ ↔ ψ
bi3.2 ⊢ χ ↔ θ
bi3.3 ⊢ τ ↔ η
Assertion 3orbi123i ⊢ φ ∨ χ ∨ τ ↔ ψ ∨ θ ∨ η

Proof

Step Hyp Ref Expression
1 bi3.1 ⊢ φ ↔ ψ
2 bi3.2 ⊢ χ ↔ θ
3 bi3.3 ⊢ τ ↔ η
4 1 2 orbi12i ⊢ φ ∨ χ ↔ ψ ∨ θ
5 4 3 orbi12i ⊢ φ ∨ χ ∨ τ ↔ ψ ∨ θ ∨ η
6 df-3or ⊢ φ ∨ χ ∨ τ ↔ φ ∨ χ ∨ τ
7 df-3or ⊢ ψ ∨ θ ∨ η ↔ ψ ∨ θ ∨ η
8 5 6 7 3bitr4i ⊢ φ ∨ χ ∨ τ ↔ ψ ∨ θ ∨ η