Metamath Proof Explorer


Theorem 4p5e9

Description: 4 + 5 = 9. (Contributed by SN, 24-Aug-2026)

Ref Expression
Assertion 4p5e9 4 + 5 = 9

Proof

Step Hyp Ref Expression
1 df-5 5 = 4 + 1
2 1 oveq2i 4 + 5 = 4 + 4 + 1
3 4cn 4
4 ax-1cn 1
5 3 3 4 addassi 4 + 4 + 1 = 4 + 4 + 1
6 4p4e8 4 + 4 = 8
7 6 oveq1i 4 + 4 + 1 = 8 + 1
8 8p1e9 8 + 1 = 9
9 7 8 eqtri 4 + 4 + 1 = 9
10 2 5 9 3eqtr2i 4 + 5 = 9