Metamath Proof Explorer


Theorem 4p5e9

Description: 4 + 5 = 9. (Contributed by SN, 24-Aug-2026)

Ref Expression
Assertion 4p5e9 ( 4 + 5 ) = 9

Proof

Step Hyp Ref Expression
1 df-5 5 = ( 4 + 1 )
2 1 oveq2i ( 4 + 5 ) = ( 4 + ( 4 + 1 ) )
3 4cn 4 ∈ ℂ
4 ax-1cn 1 ∈ ℂ
5 3 3 4 addassi ( ( 4 + 4 ) + 1 ) = ( 4 + ( 4 + 1 ) )
6 4p4e8 ( 4 + 4 ) = 8
7 6 oveq1i ( ( 4 + 4 ) + 1 ) = ( 8 + 1 )
8 8p1e9 ( 8 + 1 ) = 9
9 7 8 eqtri ( ( 4 + 4 ) + 1 ) = 9
10 2 5 9 3eqtr2i ( 4 + 5 ) = 9