Metamath Proof Explorer


Theorem 6on

Description: Ordinal 6 is an ordinal number. (Contributed by BTernaryTau, 4-Sep-2026)

Ref Expression
Assertion 6on Could not format assertion : No typesetting found for |- 6o e. On with typecode |-

Proof

Step Hyp Ref Expression
1 df-6o Could not format 6o = suc 5o : No typesetting found for |- 6o = suc 5o with typecode |-
2 5on Could not format 5o e. On : No typesetting found for |- 5o e. On with typecode |-
3 2 onsuci Could not format suc 5o e. On : No typesetting found for |- suc 5o e. On with typecode |-
4 1 3 eqeltri Could not format 6o e. On : No typesetting found for |- 6o e. On with typecode |-