Metamath Proof Explorer


Theorem abs2dif2d

Description: Difference of absolute values. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypotheses abscld.1 ⊢ φ → A ∈ ℂ
abssubd.2 ⊢ φ → B ∈ ℂ
Assertion abs2dif2d ⊢ φ → A − B ≤ A + B

Proof

Step Hyp Ref Expression
1 abscld.1 ⊢ φ → A ∈ ℂ
2 abssubd.2 ⊢ φ → B ∈ ℂ
3 abs2dif2 ⊢ A ∈ ℂ ∧ B ∈ ℂ → A − B ≤ A + B
4 1 2 3 syl2anc ⊢ φ → A − B ≤ A + B