Metamath Proof Explorer


Theorem abs3lemd

Description: Lemma involving absolute value of differences. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypotheses abscld.1 ⊢ φ → A ∈ ℂ
abssubd.2 ⊢ φ → B ∈ ℂ
abs3difd.3 ⊢ φ → C ∈ ℂ
abs3lemd.4 ⊢ φ → D ∈ ℝ
abs3lemd.5 ⊢ φ → A − C < D 2
abs3lemd.6 ⊢ φ → C − B < D 2
Assertion abs3lemd ⊢ φ → A − B < D

Proof

Step Hyp Ref Expression
1 abscld.1 ⊢ φ → A ∈ ℂ
2 abssubd.2 ⊢ φ → B ∈ ℂ
3 abs3difd.3 ⊢ φ → C ∈ ℂ
4 abs3lemd.4 ⊢ φ → D ∈ ℝ
5 abs3lemd.5 ⊢ φ → A − C < D 2
6 abs3lemd.6 ⊢ φ → C − B < D 2
7 abs3lem ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ ∧ D ∈ ℝ → A − C < D 2 ∧ C − B < D 2 → A − B < D
8 1 2 3 4 7 syl22anc ⊢ φ → A − C < D 2 ∧ C − B < D 2 → A − B < D
9 5 6 8 mp2and ⊢ φ → A − B < D