Metamath Proof Explorer


Theorem absnegd

Description: Absolute value of negative. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypothesis abscld.1 ⊢ φ → A ∈ ℂ
Assertion absnegd ⊢ φ → − A = A

Proof

Step Hyp Ref Expression
1 abscld.1 ⊢ φ → A ∈ ℂ
2 absneg ⊢ A ∈ ℂ → − A = A
3 1 2 syl ⊢ φ → − A = A