Theorem absnegd

Description: Absolute value of negative. (Contributed by Mario Carneiro, 29-May-2016)

	Ref	Expression
Hypothesis	abscld.1	⊢ ( 𝜑 → 𝐴 ∈ ℂ )
Assertion	absnegd	⊢ ( 𝜑 → ( abs ‘ - 𝐴 ) = ( abs ‘ 𝐴 ) )

Proof

Step	Hyp	Ref	Expression
1		abscld.1	⊢ ( 𝜑 → 𝐴 ∈ ℂ )
2		absneg	⊢ ( 𝐴 ∈ ℂ → ( abs ‘ - 𝐴 ) = ( abs ‘ 𝐴 ) )
3	1 2	syl	⊢ ( 𝜑 → ( abs ‘ - 𝐴 ) = ( abs ‘ 𝐴 ) )