Metamath Proof Explorer


Theorem absvalsq2d

Description: Square of value of absolute value function. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypothesis abscld.1 φA
Assertion absvalsq2d φA2=A2+A2

Proof

Step Hyp Ref Expression
1 abscld.1 φA
2 absvalsq2 AA2=A2+A2
3 1 2 syl φA2=A2+A2