Metamath Proof Explorer


Theorem alcomimw

Description: Weak version of ax-11 . See alcomw for the biconditional form. Uses only Tarski's FOL axiom schemes. (Contributed by NM, 10-Apr-2017) (Proof shortened by Wolf Lammen, 28-Dec-2023)

Ref Expression
Hypothesis alcomimw.1 ⊢ y = z → φ ↔ ψ
Assertion alcomimw ⊢ ∀ x ∀ y φ → ∀ y ∀ x φ

Proof

Step Hyp Ref Expression
1 alcomimw.1 ⊢ y = z → φ ↔ ψ
2 1 cbvalvw ⊢ ∀ y φ ↔ ∀ z ψ
3 2 biimpi ⊢ ∀ y φ → ∀ z ψ
4 3 alimi ⊢ ∀ x ∀ y φ → ∀ x ∀ z ψ
5 ax-5 ⊢ ∀ x ∀ z ψ → ∀ y ∀ x ∀ z ψ
6 1 biimprd ⊢ y = z → ψ → φ
7 6 equcoms ⊢ z = y → ψ → φ
8 7 spimvw ⊢ ∀ z ψ → φ
9 8 2alimi ⊢ ∀ y ∀ x ∀ z ψ → ∀ y ∀ x φ
10 4 5 9 3syl ⊢ ∀ x ∀ y φ → ∀ y ∀ x φ