Metamath Proof Explorer


Theorem animorr

Description: Conjunction implies disjunction with one common formula (2/4). (Contributed by BJ, 4-Oct-2019)

Ref Expression
Assertion animorr ⊢ φ ∧ ψ → χ ∨ ψ

Proof

Step Hyp Ref Expression
1 simpr ⊢ φ ∧ ψ → ψ
2 1 olcd ⊢ φ ∧ ψ → χ ∨ ψ