Metamath Proof Explorer


Theorem asclelbas

Description: Lifted scalars are in the base set of the algebra. (Contributed by Zhi Wang, 11-Sep-2025) (Proof shortened by Thierry Arnoux, 22-Sep-2025)

Ref Expression
Hypotheses asclelbas.a ⊢ A = algSc ⁡ W
asclelbas.f ⊢ F = Scalar ⁡ W
asclelbas.b ⊢ B = Base F
asclelbas.w ⊢ φ → W ∈ AssAlg
asclelbas.c ⊢ φ → C ∈ B
Assertion asclelbas ⊢ φ → A ⁡ C ∈ Base W

Proof

Step Hyp Ref Expression
1 asclelbas.a ⊢ A = algSc ⁡ W
2 asclelbas.f ⊢ F = Scalar ⁡ W
3 asclelbas.b ⊢ B = Base F
4 asclelbas.w ⊢ φ → W ∈ AssAlg
5 asclelbas.c ⊢ φ → C ∈ B
6 assaring ⊢ W ∈ AssAlg → W ∈ Ring
7 4 6 syl ⊢ φ → W ∈ Ring
8 assalmod ⊢ W ∈ AssAlg → W ∈ LMod
9 4 8 syl ⊢ φ → W ∈ LMod
10 eqid ⊢ Base W = Base W
11 1 2 7 9 3 10 asclf ⊢ φ → A : B ⟶ Base W
12 11 5 ffvelcdmd ⊢ φ → A ⁡ C ∈ Base W