Metamath Proof Explorer


Theorem asclelbas

Description: Lifted scalars are in the base set of the algebra. (Contributed by Zhi Wang, 11-Sep-2025) (Proof shortened by Thierry Arnoux, 22-Sep-2025)

Ref Expression
Hypotheses asclelbas.a ⊢ 𝐴 = ( algSc ‘ 𝑊 )
asclelbas.f ⊢ 𝐹 = ( Scalar ‘ 𝑊 )
asclelbas.b ⊢ 𝐵 = ( Base ‘ 𝐹 )
asclelbas.w ⊢ ( 𝜑 → 𝑊 ∈ AssAlg )
asclelbas.c ⊢ ( 𝜑 → 𝐶 ∈ 𝐵 )
Assertion asclelbas ( 𝜑 → ( 𝐴 ‘ 𝐶 ) ∈ ( Base ‘ 𝑊 ) )

Proof

Step Hyp Ref Expression
1 asclelbas.a ⊢ 𝐴 = ( algSc ‘ 𝑊 )
2 asclelbas.f ⊢ 𝐹 = ( Scalar ‘ 𝑊 )
3 asclelbas.b ⊢ 𝐵 = ( Base ‘ 𝐹 )
4 asclelbas.w ⊢ ( 𝜑 → 𝑊 ∈ AssAlg )
5 asclelbas.c ⊢ ( 𝜑 → 𝐶 ∈ 𝐵 )
6 assaring ⊢ ( 𝑊 ∈ AssAlg → 𝑊 ∈ Ring )
7 4 6 syl ⊢ ( 𝜑 → 𝑊 ∈ Ring )
8 assalmod ⊢ ( 𝑊 ∈ AssAlg → 𝑊 ∈ LMod )
9 4 8 syl ⊢ ( 𝜑 → 𝑊 ∈ LMod )
10 eqid ⊢ ( Base ‘ 𝑊 ) = ( Base ‘ 𝑊 )
11 1 2 7 9 3 10 asclf ⊢ ( 𝜑 → 𝐴 : 𝐵 ⟶ ( Base ‘ 𝑊 ) )
12 11 5 ffvelcdmd ⊢ ( 𝜑 → ( 𝐴 ‘ 𝐶 ) ∈ ( Base ‘ 𝑊 ) )