Metamath Proof Explorer


Theorem axc16nfALT

Description: Alternate proof of axc16nf , shorter but requiring ax-11 and ax-13 . (Contributed by Mario Carneiro, 7-Oct-2016) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion axc16nfALT xx=yzφ

Proof

Step Hyp Ref Expression
1 nfae zxx=y
2 axc16g xx=yφzφ
3 1 2 nf5d xx=yzφ