Metamath Proof Explorer


Theorem axc5c711toc5

Description: Rederivation of ax-c5 from axc5c711 . Only propositional calculus is used by the rederivation. (Contributed by NM, 19-Nov-2006) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion axc5c711toc5 ⊢ ∀ x φ → φ

Proof

Step Hyp Ref Expression
1 ax-1 ⊢ ∀ x φ → ∀ x ∀ x ¬ ∀ x ∀ x φ → ∀ x φ
2 axc5c711 ⊢ ∀ x ∀ x ¬ ∀ x ∀ x φ → ∀ x φ → φ
3 1 2 syl ⊢ ∀ x φ → φ