Metamath Proof Explorer


Theorem bj-cbvex2vv

Description: Version of cbvex2vv with a disjoint variable condition, which does not require ax-13 . (Contributed by BJ, 16-Jun-2019) (Proof modification is discouraged.)

Ref Expression
Hypothesis bj-cbval2vv.1 ⊢ x = z ∧ y = w → φ ↔ ψ
Assertion bj-cbvex2vv ⊢ ∃ x ∃ y φ ↔ ∃ z ∃ w ψ

Proof

Step Hyp Ref Expression
1 bj-cbval2vv.1 ⊢ x = z ∧ y = w → φ ↔ ψ
2 nfv ⊢ Ⅎ z φ
3 nfv ⊢ Ⅎ w φ
4 nfv ⊢ Ⅎ x ψ
5 nfv ⊢ Ⅎ y ψ
6 2 3 4 5 1 cbvex2v ⊢ ∃ x ∃ y φ ↔ ∃ z ∃ w ψ