Metamath Proof Explorer


Theorem bj-disjcsn

Description: A class is disjoint from its singleton. A consequence of regularity. Shorter proof than bnj521 and does not depend on df-ne . (Contributed by BJ, 4-Apr-2019)

Ref Expression
Assertion bj-disjcsn A A =

Proof

Step Hyp Ref Expression
1 elirr ¬ A A
2 disjsn A A = ¬ A A
3 1 2 mpbir A A =