Metamath Proof Explorer


Theorem bj-disjsn01

Description: Disjointness of the singletons containing 0 and 1. This is a consequence of disjcsn but the present proof does not use regularity. (Contributed by BJ, 4-Apr-2019) (Proof modification is discouraged.)

Ref Expression
Assertion bj-disjsn01 ⊢ ∅ ∩ 1 𝑜 = ∅

Proof

Step Hyp Ref Expression
1 1n0 ⊢ 1 𝑜 ≠ ∅
2 1 necomi ⊢ ∅ ≠ 1 𝑜
3 disjsn2 ⊢ ∅ ≠ 1 𝑜 → ∅ ∩ 1 𝑜 = ∅
4 2 3 ax-mp ⊢ ∅ ∩ 1 𝑜 = ∅