Metamath Proof Explorer


Theorem bj-disjsn01

Description: Disjointness of the singletons containing 0 and 1. This is a consequence of bj-disjcsn but the present proof does not use regularity. (Contributed by BJ, 4-Apr-2019) (Proof modification is discouraged.)

Ref Expression
Assertion bj-disjsn01 1 𝑜 =

Proof

Step Hyp Ref Expression
1 1n0 1 𝑜
2 1 necomi 1 𝑜
3 disjsn2 1 𝑜 1 𝑜 =
4 2 3 ax-mp 1 𝑜 =