Metamath Proof Explorer


Theorem disjsn2

Description: Two distinct singletons are disjoint. (Contributed by NM, 25-May-1998)

Ref Expression
Assertion disjsn2 ⊢ A ≠ B → A ∩ B = ∅

Proof

Step Hyp Ref Expression
1 elsni ⊢ B ∈ A → B = A
2 1 eqcomd ⊢ B ∈ A → A = B
3 2 necon3ai ⊢ A ≠ B → ¬ B ∈ A
4 disjsn ⊢ A ∩ B = ∅ ↔ ¬ B ∈ A
5 3 4 sylibr ⊢ A ≠ B → A ∩ B = ∅