Metamath Proof Explorer


Theorem bj-disjsn01

Description: Disjointness of the singletons containing 0 and 1. This is a consequence of bj-disjcsn but the present proof does not use regularity. (Contributed by BJ, 4-Apr-2019) (Proof modification is discouraged.)

Ref Expression
Assertion bj-disjsn01 ( { ∅ } ∩ { 1o } ) = ∅

Proof

Step Hyp Ref Expression
1 1n0 1o ≠ ∅
2 1 necomi ∅ ≠ 1o
3 disjsn2 ( ∅ ≠ 1o → ( { ∅ } ∩ { 1o } ) = ∅ )
4 2 3 ax-mp ( { ∅ } ∩ { 1o } ) = ∅