Metamath Proof Explorer


Theorem bj-hbnaeb

Description: Biconditional version of hbnae (to replace it?). (Contributed by BJ, 6-Oct-2018)

Ref Expression
Assertion bj-hbnaeb ⊢ ¬ ∀ x x = y ↔ ∀ z ¬ ∀ x x = y

Proof

Step Hyp Ref Expression
1 hbnae ⊢ ¬ ∀ x x = y → ∀ z ¬ ∀ x x = y
2 sp ⊢ ∀ z ¬ ∀ x x = y → ¬ ∀ x x = y
3 1 2 impbii ⊢ ¬ ∀ x x = y ↔ ∀ z ¬ ∀ x x = y